Math Puzzle – Timpkinses Ages Problem

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Edwin: “Do you know, when the Timpkinses married eighteen years ago Timpkins was three times as old as his wife, and to-day he is just twice as old as she?”

Angelina: “Then how old was Mrs. Timpkins on the wedding day?”

Can you answer Angelina’s question?

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Founder at Durofy. Blogs on technology & startups, runs a full service digital agency, teaches AP Calculus.

3 Comments

  1. Let X = MR. TIMPKINS
    Let Y = MRS. TIMPKINS

    18 years ago: (X-18)=3(Y-18)
    Today: X=2Y

    Solving:

    X-18=3Y-54

    Substitute X=2Y

    2Y-18=3Y-54
    Y=36

    Subract 18 from this (required by question) = MRS. TOMPKINS was 18 YEARS OLD on her wedding day. Good job kavita!